I always have trouble remembering how to do the Fisher's exact test in R.
So here it is!
To test whether 393/1832 is significantly different from 2/36:
> fisher.test(matrix(c(393,2,1832-393,36-2),nrow=2))
Fisher's Exact Test for Count Data
data: matrix(c(393, 2, 1832 - 393, 36 - 2), nrow = 2)
p-value = 0.02115
alternative hypothesis: true odds ratio is not equal to 1
95 percent confidence interval:
1.180687 40.036943
sample estimates:
odds ratio
4.640479
The P-value is 0.02115.
No comments:
Post a Comment